binomial theorem

Question

The cube root 217 is?

 

how to do it with binomial expansion?

Answer 1

Binomial SERIES

 

using the formula fromn your other problem on (1+6^3)^1/3 you'd get...

 

1 + 1/3 *6 + 1/3*(-2/3)*(1/2!)* 6^2 + (1/3)(-2/3)(-5/3)(1/3!) 6^3 +.....+ (1/3)(1/3 -1)(1/3 -2)...(1/3-n+1) divided by n! * 6^n