Graph 6x+2Y=4

Question

I'm suppose to graph and show my work 

Answer 1

This is the equation of a straight line in standard form.  To graph a straight line, you just need to find two points on the line in (x,y) format, plot the points on the graph, then use a straight edge to draw the line that goes through those two points.

 

The two points that are easiest to find when the equation is in standard form are the x and y intercepts of the line.  The x-intercept occurs when y=0.  To find it, set y = 0 in the standard form equation and solve for x:

 

6x + 2y = 4

6x + 2*0 = 4

6x = 4

x = 2/3

 

The x-intercept occurs at the point (2/3,0).  Plot that point on your graph.

 

The y-intercept occurs when x = 0.  To find it, set x = 0 in the 6x + 2y = 4 equation and solve for y.  The y-intercept occurs at the point (0,b) where b is the value you get when you solve for y.  Plot that point of the graph and use your straight edge to draw the line that goes through the two plotted points.

 

See the graph here: http://www.wyzant.com/resources/files/291703/graph_of_line_in_standard_form

Answer 2

Hello, Melissa from Apple Valley

 

6x  +    2y     =  4                This is called the Standard Form

-6x                     -6x            Subtract 6x from both sides

            2y   = -6x +4           Divide both sides by 2

              Y= -3x + 2             The slope-intercept form

 

Ok, go to (0,2) on the y axis and plot a point.  This is called the y intercept.  Next, from this point, go down three units and one unit to the right and plot this point. This point should be (1, -1), which is located on quadrant IV.  Now connect (0,2) and (1,-1) with a line, not a line segment.  In other words, don't just stop at the points, extend the line.  And there you have it.  I am glad to help.  If you have any other question just post them.

 

 Note: you can also do it like the other tutor showed you.. I just took a different approach.

 

D.Y. T