
Jay T. answered 08/22/18
Tutor
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Retired Engineer/Math Tutor
Since sqrt(x^2)=x, the equation becomes
3x(y^3)/(x^2)sqrt(y)
In exponential notation:
sqrt(y) is y^(1/2)
1/x^2 is x^(-2)
1/y^(1/2) is y^(-1/2)
So the equation becomes:
3x(y^3)(x^(-2))(y^(-1/2))
For any exponent, (z^a)(x^b)=z^(a+b), so the equation becomes
3x^(1-2)y^(3-1/2) = 3x^(-1)y^(2 1/2), or equivalently,
3y^2(sqrt(y)/x
3x(y^3)/(x^2)sqrt(y)
In exponential notation:
sqrt(y) is y^(1/2)
1/x^2 is x^(-2)
1/y^(1/2) is y^(-1/2)
So the equation becomes:
3x(y^3)(x^(-2))(y^(-1/2))
For any exponent, (z^a)(x^b)=z^(a+b), so the equation becomes
3x^(1-2)y^(3-1/2) = 3x^(-1)y^(2 1/2), or equivalently,
3y^2(sqrt(y)/x