Theta of right triangle

Question

c=30 and b=32, solve for a and theta

Answer 1

Bigger problems that that...

 

Assuming the hypotenuse is 32 we have

 

a = sqrt( 32^2 - 30^2)

 

  = sqrt( 1024 - 900)

  = sqrt( 124)

  = sqrt( 2* 2 * 31)

  = 2 * sqrt(31) = 11.13552872566....

 

The angle opposite side a:

   sine is 2*sqrt(31)/32 = sqrt(31)/16

 

     THe angle then is inverse-sine of sqrt(31)/16

     which is ABOUT 44.104607....

 

 The angle opposite the side of measure 30 :

   sine is 30/32 = 15/16

 

 That angle is inverse-sine(15/16) = 69.6358652...

 

THe problem is those angles are NOT complementary

and WORSE yet, there are more than 180 degrees 

in the triangle.

 

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