The length of a rectangle is 3ft more than double the width, and the area of the rectangle is 35ft^2. Find the dimensions of the rectangle.

Question

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Answer 1

simultaneous equations:

 

a = l x w

l = 2w +3

 

a = (2w + 3)w= 35

 

2w^2 + 3w = 35

 

2w^2 + 3w  - 35 = 0

 

Factor ( or use quadratic eq.):

 

(2w - 7) (w + 5) = 0

 

w = 7/2  (also, w = -5, but a width can not be a negative number)