find the speed of the bus

Question

A bus leaves station A at 9:00 a.m. and ahead towards 220 miles away an hour later another bus leaves station A it travels twice as last as the first bus arrives in the city 2 hrs ahead of the first bus find speed of the bus

Answer 1

If I understand your question: 

 

One bus leaves station A at 9am going to the city which is 220 mi away. 

A 2nd bus leaves an hour later, but traveling twice as fast. It arrives at the city 2 hours before the first bus. 

Correct ?? 

 

Ok, just use Speed (S) x Time = Distance

Bus 1 = moving at speed S

Bus 2, is going twice as fast  OR  2S

 

Bus 2 left 1 hour after Bus 1, and arrived 2 hours earlier. 

It Time then was 3 hours less than Bus 1, OR  T-3. 

 

using Speed x Time = Dist

 

Bus 1:   S (T) = 220

Bus 2:   (2S) (T - 3) = 220 

 

set equations equal, since both = 220

 

ST = 2ST - 6S 

or rearrange to    6S = 2ST - ST or

6S = ST    divide out the S

6 = T    so Bus 1 spent 6 hrs to go 220 mi

 

Speed of Bus 1 is Dist/Time = 220/6 = 36.67 mi/hr 

 

Bus 2 was going 2x that or 73.33 mi/hr and traveled for 3 hrs