In a certain​ fractionthe denominator is 4 less than the numerator.

Question

In a certain fractionthe denominator is 4 less than the numerator. If 3 is added to both the numerator and denominator, the resulting fraction is equal to three halves . Translate the given statements into an equation that can be used to solve for x.

Answer 1

X/X-4

(X+3)/(X-4+3)=3/2

if you want the answer...

cross multiply

2(X+3)=3(X-1)

2X+6=3X-3

6+3=3X-2X

X=9

9/5 is the original fraction

(9+3)/(5+3)=12/8=3/2

Answer 2

Let the number in the numerator =x

First statement:  x/(x-4)

Second Statement: (x+3)/[(x-4)+3]=3/2

Cross Multiply

2(x+3)=3[(x-4)+3]

2x+6=3x-3

collect variables to the Right and constants to the left

6+3=3x-2x

9=x

Check: substitute x=9 into second statement