Jane X. answered 07/22/18
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Experienced Algebra1 Tutor: Teacher certified in Math4-12/Physics 8-12
There are three forms of linear equations,
the point-slope form: y-y1=m(x-x1). M is slope (X1 , y1) is the point
the slope -intercept form: y=mx+b m is the slope, b is the y intercept
the standard form: Ax+By=C , with A,B, C are integers, A has to be positive
so for this question the given is m=4, the point is (-1, 2) , we can write the equation in point slope form:
y-2=4(x+1)
then distribute 4 and simplify y-2=4x+4 , y=4x+6 is the slope -y intercept form
then, move 4x on the left side, you get -4x+y=6 , multiply every term by -1, you get 4x-y=-6 which is standard form.