Mark M. answered 07/18/18
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
h(x) = x2√(8-x)
By the Product Rule, h'(x) = 2x√(8-x) + ½(8-x)-½(-1)x2
= 2x√(8-x) - x2 / [2√(8-x)]
= [4x(8-x) - x2] / [2√(8-x)]
= (32x - 5x2) / [2√(8-x)]