A rectangular painting is three times as long as it is wide. The area of the picture is 588 in^2. Find the dimensions of the painting.

Question

 I dont know it.

Answer 1

Hello John

 

Let l = length and w = width

 

Length of painting is 3 times its width or l = 3w

 

Area, A = l x w = 588 in²

 

 

Substitute l =3w in the above equation and first solve for the width.

 

3w x w = 588

3w² = 588

w² = 196

w = √196 = 14 in

 

Length, l = 3w = 3 x 14 = 42 in

 

To ensure the values are correct, solve for A using l = 42 in and w = 14 in.

 

A = 42 x 14 = 588 in²!