What is the equation of the line that passes through (5, -2) and (-3, 4)?

Question

 I need the answer

Answer 1

To find the solution, we can use the slope-intercept formula which is y=mx + b. Here, m is the slope which has formula

m=(y2-y1)/(x2-x1) and b is the y-intercept. 

 

Let us find the slope first. Using our two points we get m=(y2-y1)/(x2-x1) = (4--2)/(-3-5) = 6/-8 which reduces to -3/4.

 

We can choose either point given to solve from here. I will choose (-3,4). So, we have:

 

y=mx + b

 

4 = (-3/4)(-3) + b

 

4 = 9/4 + b

 

4 - 9/4 = b

 

16/4 - 9/4 = b

 

7/4 = b

 

Plugging m and b in we get y=(-3/4)x + 7/4