write an equation that contains the points, (-2, -2) and (4, 10)?

Question

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Answer 1

OK. The equation of a line is :

(y-y1) = m(x-x1)    

 

First, calculate the slope (m)

m = change in y/change in x

m = (10-(-2))/(4-(-2)) = 12/6 = 2

Now we have:

(y-y1) = 2(x-x1)

Now substitute one of the given points for (x1, y1)

 

(y - (-2)) = 2 (x- (-2))

y +2 = 2(x + 2)

y + 2 = 2x + 4

y = 2x + 2

 

Now check: 

(substitute point (4,10) into equation):

10 = 2(4) + 2

10 = 8 + 2 = 10

 

y = 2x +2 is your answer