area,perimeter,volume

Question

area,perimeter,volume

The rectangular backboard of a basketball court needs to be assembled. Its area is given as 18,900 cm2 and the width as 1.8 m. What is the backboard’s length in meters? m

Answer 1

The first step is converting the given area, 18,900 cm² into m².

 

1 cm = 1/100 m.

To convert to cm² and m², square both sides.

1 cm x 1 cm = (1/100) m x (1/100) m

1 cm² = (1/10,000) m²

 

Now we can convert the given area from cm² to m². Since meters are larger than centimeters, we can expect the number to go down. So divide 18,900 by 10,000, to get 1.89 m².

 

Then you use the equation for the area of a rectangle (Area=length x width).

 

1.89 = length x 1.8

Solve for length.

 

 

 

 

Answer 2

Area od a rectangle is A=L*W; they tell you that the area is A=18,900 so L*W=18,900 cm^2

since the width is 1.8 m^2 and the Area is in cm^2 units we need to change the area to m^2:

 

10,000 cm^2 is 1 m^2 then:

 

18,900 cm^2  x  1m^2/10000 cm^2   1.89 m^2

 

with the formula   L*W=1.89    L*1.8=1.89     L=1.89/1.8     L=1.05 m

 

Answer 3

The area of a rectangle is length x width

 

The area is given as 18,900 cm² and the width is 1.8 m

 

These need to be in the same unit, either cm or m

 

1 m = 100 cm

 

change the 1.8 m width to cm by multiplying by 100

 

1.8 x 100 = 180 cm

 

plug in 180 for the width

 

again, area = L x W

so 18,900 = L x180

 

L = 105 cm

 

The question asked for the length in meters so convert back

 

105 cm ÷ 100 = 1.05 meters

 

Answer: 1.05 meters