a + b = 8000

0.08a + 0.1b = 660

a = 8000 - b

0.08(8000 - b) + 0.1b = 660

640 - 0.08b + 0.1b = 660

0.02b = 20

b = 1000

a = 8000 - 1000

a = 7000

Jenna A.

asked • 06/26/18A woman has a total of $8,000 to invest. She invests part of the money in an account that pays 8% per year and the rest in an account that pays 10% per year. If the interest earned in the first year is $660, how much did she invest in each account?

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a + b = 8000

0.08a + 0.1b = 660

a = 8000 - b

0.08(8000 - b) + 0.1b = 660

640 - 0.08b + 0.1b = 660

0.02b = 20

b = 1000

a = 8000 - 1000

a = 7000

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