which of following equations describes the line (1,10) (-3,2)

Question

A. y-3=2(x-2)

B. y-2=2(x-3)

C. y-10=2(x-1)

D.y-2=2(x+3)

E. y-1=2(x-10)

F. y+3=2(x-2)

Answer 1

Ok. First you need the point-slope formula for a line.

y-y1=m(x-x1)  where m=slope 

Using the points (1,10) (-3,2) we calculate the slope :

(10-2)/(1-(-3)) = 8/(1+3) = 2

So now you have y-y1=2(x-x1)

now substitute one of the points in the problem. 

Using (-3,2)  we get:

y-2=2(x+3)

Using (1,10), we get

y-10=2(x-1)

So answers C and D are both correct.