Amanda R.
asked • 06/10/18Find two consecutive integers such that half times the first added to twice the second sums to 57
Having trouble solving this problem. Please help!!
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1 Expert Answer
Arturo O. answered • 06/10/18
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The 2 consecutive integers are n and n + 1.
(1/2)n + 2(n + 1) = 57
Can you solve for n and finish from here?
Amanda R.
Thank you for the formulation. I'm in remedial math and a little confused. Am I looking for two different numbers or does consecutive mean the same number for (n)
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06/10/18
Arturo O.
You will solve for just one n to get the first number, and then add 1 to it to get the second number, since they are consecutive numbers.
(1/2)n + 2(n + 1) = 57
Multiply both sides by 2:
n + 4(n + 1) = 114
n + 4n + 4 = 114
5n + 4 = 114
5n = 114 - 4 = 110
n = 110/5 = 22
n + 1 = 22 + 1= 23
You can plug these 2 numbers back into the original question to test the answer.
(1/2)(22) + 2(23) = 57
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06/10/18
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David W.
06/10/18