Haley B.

asked • 06/07/18# What is the concentration of each gas once equilibrium is reached?

Can someone please let me know if I did this right?

1.800 mole of N

_{2}O_{4}(g) is injected into a closed 1.00L container._{}K

_{c}=4.66 x 10^{-3}at 298KN

_{2}O_{4}(g) ⇌ 2NO_{2}(g)what is the concentration of each gas once equilibrium is reached?

I set up an ICE table as follows:

I 1.80 0

C -x +2x

E 1.80-x 2x

then input the values from row E into K

_{c}equation:4.66 x 10

^{-3}= (2x)^{2} (1.80-x)

using the quadratic equation I found x= 0.0452, and x= -0.0463

using the positive value for x to find the concentrations of each gas at equilibrium, I found:

[N

_{2}O_{4}]= 1.80-x 1.80-0.0452

1.75M

[NO

_{2}]= 2x 2(0.0452)

0.0904M

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## 2 Answers By Expert Tutors

J.R. S. answered • 06/08/18

Tutor

5.0
(110)
Ph.D. University Professor with 10+ years Tutoring Experience

Yes. You did do this correctly.

NOTE: I didn't check the math but the approach is spot-on.

You did this correctly &^ I checked your work.

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J.R. S.

06/09/18