Bobosharif S. answered 05/13/18
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PhD in Math, MS's in Calulus
logb2=.36 and logb5=.83
i) logb25=logb52=2logb5=2*0.83=..
ii) logb20=logb(22*5)=2logb2+logb5=2*0.36+0.83=..
ii) logb√20=(1/2)logb20=(1/2) (2*0.36+0.83)=..
iv) What is b
logb2=.36
b0.36=2
20.36log2b=2
log2b=2/0.36=50/9
b=250/9
i) logb25=logb52=2logb5=2*0.83=..
ii) logb20=logb(22*5)=2logb2+logb5=2*0.36+0.83=..
ii) logb√20=(1/2)logb20=(1/2) (2*0.36+0.83)=..
iv) What is b
logb2=.36
b0.36=2
20.36log2b=2
log2b=2/0.36=50/9
b=250/9
Bobosharif S.
1 and 2, seem to be correct, but I've got a different number.
Check out from the beginning to the end.
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05/13/18
Will B.
05/13/18