Jane X. answered 04/28/18
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Experienced Geometry Tutor: Teacher certified in Math/Physics 4-12
If you assume this is isosceles triangle, then you can solve it , otherwise it's not solvable ( not enough information)
set half of the base is x
the 2sqroot(x2+482)+2x=128
sqroot(x2+482)=64-x
x2+482=642-128x+x2
x=14
A=1/2*28*48=672