Olivia L.
asked 04/24/18
Give the equation of the line, in standard form, that runs through (2, -2) and is perpendicular to x-3y=7
Line: x-3y=7
Points: (2,-2)
-3y = - x + 7
y = (1/3)x - 7/3
y - (-2) = -3(x - 2)
y + 2 = -3x + 6
3x + y = 4
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