Mark M. answered 04/14/18
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Limx→1- f(x) = 3(1)2-5 = -2 and limx→1+ f(x) = 6(1)+2 = 8
Since the one-sided limits are unequal, I is FALSE.
Since I is false, the function is not continuous at x = 1. Therefore, the function is not differentiable at x = 1 either. So, III is also FALSE.
limx→1- f'(x) = 6(1) = 6 and limx→1+ f'(x) = 6.
Since the one-sided limits are the same, limx→1f'(x) = 6
So, II is TRUE.