J.R. S. answered 04/13/18
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
Final volume of solution = 100 ml + 200 ml = 300 ml = 0.3 L
Ce(NO3)3 + 3KIO3 ==> Ce(IO3)3 + 3KNO3
Find moles Ce(IO3)3 produced:
moles Ce(NO3)3 = 0.1 L x 1.0x10-2 mol/L = 1.0x10-3 moles
moles KIO3 = 0.2 L x 2x10-3 mol/L = 4x10-4 moles = LIMITING REACTANT
moles Ce(IO3)3 formed = 1/3 x 4x10-4 moles = 1.3x10-4 moles
Final [Ce(IO3)3 = 1.3x10-4 mol/0.3 L = 4.4x10-4 M
Q = [Ce3+][IO3-]3
Q = (4.4x10-4)(4.4x10-4)3 = 3.75x10-14
Q < Ksp therefore NO PRECIPITATE FORMS