Find three consecutive integers such that the sum of the second and third is 8 less that three times the first

Question

I have no idea how to do these. Please help.

Answer 1

The 3 consecutive integers must be

 

1st:  n

2nd:  n + 1

3rd:  n + 2

 

You were given that

 

(n + 1) + (n + 2) = 3n - 8

 

Can you solve for n and finish from here?