J.R. S. answered 04/01/18
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6H2O + 6CO2 => C6H12O6 + 6O2 .. balanced eq
moles H2O used=1.5 g x 1moke/18g = 0.0833 mol
moles Glucose formed = 0.0833 mol H2O x 1 mol glucose/6 mol H2O = 0.0139 moles glucose
mass glucose = 0.0139 moles x 180 g/ mole = 2.5 g