Write an equation for the line parallel to y = 7x + 10 that contains P(–1, 2).

Question

Please show all work.

Answer 1

Write an equation for the line parallel to y = 7x + 10 that contains P(–1, 2).
Please show all work.

 

Solution:

 

The equation of the line that is parallel to the line y=7x+10 and passing through the point ( -1,2) has the same slope of that line. Therefore The slope is m=7

Using the slope and the point you can write the equation in point slope form as:

 

m= y-2/x+1, y-2=m(x+1), substituting for m , y-2=7(x+1)

 

y-2=7x+7, in general form the equation becomes y-7x-9=0

                 in y intercept form the equation becomes y=7x+9 

Remember that the equation of the line in y intercept form is y=mx+b where m=7, and b=9, and the line intersects the y axis at the point (0,b)

or (0,9) in our equation