Amr O.

asked • 09/15/14

In triangle ABC: B , C are two acute angles

AD is drawn perpendicular to BC ,m(BAD)=alpha,and m(CAD)=beta
Prove that:AD=a*cos(alpha)*cos(beta)/sin(alpha+beta)
 

1 Expert Answer

By:

Phillip R. answered • 09/15/14

Top Notch Math and Science Tutoring from Brown Univ Grad

Amr O.

Thanks for the answer I just wanna ask you to explain how 
sin(alpha)cos(beta)+sin(beta)cos(alpha) =sin(alpha+beta)
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09/15/14

Amr O.

Oh yes thank thats trigonometrical identity I remembered it now thanks for the answer again
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09/15/14

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