How do i work this problem?

Question

B² -5b-6=0

Answer 1

To "work" this problem, first you have to write it correctly, and be a little more specific about your question.

Assuming that you'd like to solve equation b²-5b-6=0 (lowercase b instead of B), you can find its roots in different ways. Since 

b²-5b-6=(b+1)(b-6), then

b2-5b-6=0

(b+1)(b-6)=0

So b=-1 and b=6 are the two real roots.

 

Answer 2

I assume B is the same as b and that you want to solve for b.

 

b² - 5b - 6 = 0

 

Try factoring the expression on the left, and get

 

(b - 6)(b + 1) = 0

 

b = 6 or -1