hi.... i ve got this exercice here, 0.1=1/1+(1-w^2*0.1*0.01/w*10*0.01) how should i proceed? thanks

Question

0.1=                   1                         
        1+(1-w2*0.1*0.01/w*10*0.01)

Answer 1

Approach it just like any other algebra problem. 

 

1. To get rid of that horrendous fraction, multiply both sides by the denominator. You should now have:

0.1*[1+(1-w²*0.1*0.01/w*10*0.01)] = 1

 

2. Divide both sides by 0.1. This gives you:

1+(1-w2*0.1*0.01/w*10*0.01) = 10

 

3. Subtract 1 from each side.

1-w2*0.1*0.01/w*10*0.01 = 9

 

4. Rearrange your terms so that the Ws are together; this will make it easier to look at, if anything.

1 - w² * 0.1/w * 0.1 * 10 *0.1 = 9

 

5. Since you have w2*0.1/w, the w in the denominator cancels and you are left with just the numerator of that fraction, 0.1, and w² becomes w.

1 - w * 0.1 * 0.1 * 10 *0.1 = 9

 

6. Since order of operations says that multiplication goes before subtraction, now multiply out all those numbers.

1 - w * 0.01 = 9

 

7. Subtract 1 from each side.

- 0.01w = 8

 

8. Divide by -0.01
w = 900

 

Voila.