Calculate the volume of co2 in l, produced when 300 g of butane is burned is burned completely in oxygen. The gas volume is measured at slc

Question

I don’t understand how to find the mole using only the kg of butane

Answer 1

You MUST write a balanced equation and determine moles, then volume.

Butane is C₄H₁₀ so balanced equation is:  2C₄H10 + 13O₂ ==> 8CO₂ + 10H₂O

300 g C₄H₁₀ x 1 mole/58.12 g = 5.16 moles

moles of CO₂ formed = 5.16 moles C₄H₁₀ x 8 moles CO₂/2 moles C₄H₁₀ = 20.6 moles CO₂ formed

SLC is not very common but probably refers to Standard Laboratory Conditions, which I take to mean 

298.15 K)and 0.987 atm.  This being the case, substitute these values in the ideal gas equation and solve for volume.

PV = nRT

V = nRT/P = (20.6)(0.0821)(298.15)/0.987

V = 511 liters CO₂