Jim J.

asked • 02/22/18

Gas law question

Sulfur trioxide, SO3 (g), decomposes into sulfur dioxide gas and oxygen gas according to
the following equation:

2SO3 (g) → 2SO2 (g) + O2 (g)

Assuming the reaction fully completes explain why, when this reaction takes place
at constant pressure and temperature, the volume of the product gases is 50% larger
than the original volume of the SO3.

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