how do i write in standard a+ib form?

Question

{(1-√3i)/(1+√3i)}^6 this is the question i want to write it in standard a+ib form.

Answer 1

{(1-√3i)/(1+√3i)}^6 =z^6

z=(1-√3i)/(1+√3i)=(1-√3i)²/4=(4-2√3)/4=1-(√3/2)i

Now you can expand z^6, but it is easier to write trigonometric or exponential form of z: z=|z|e^iφ