Michael P. answered • 02/19/18

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equation of line: y = m*x + b where: m = slope of line (rise/run) and b = y-intercept

The line must pass through point (2,-7) or x0 = 2 and y0 = -7

rearranging 5*x + 4*y = 7 equation in eqn of line form: y = m*x + b

4*y = -5*x + 7

y = -(5/4)*x + 7/4 therefore, slope = m = -5/4

For another line to be parallel to given line it must have the same slope, m = -5/4

Now use point that the line must pass through:

y - y0 = m*(x - x0) where: x0 = 2 and y0 = -7

y - (-7) = (-5/4)*(x - 2)

y + 7 = (-5/4)*x + 5/2

y = (-5/4)*x + 5/2 - 14/2

y = (-5/4)*x - 9/2 Therefore, this line is parallel to the given line and passes through (2,-7)