Solve this radical equation

Question

2√5x+4−2√x=4

Answer 1

2√(5x+4) = 4 + 2√x

 

Divide by 2:  √(5x+4) = 2 + √x

 

Square both sides:  5x+4 = 4 + 4√x + x

 

Isolate the remaining radical:  4√x = 4x

 

Divide by 4:  √x = x

 

Square both sides:  x = x²

 

So, x² - x = 0

 

     x(x-1) = 0     x = 0 or x = 1

 

Checking in the original equation, we see that both values are valid.