How do I solve this Chemistry problem on cobra venom

Question

Cobra venom helps the snake secure food by binding to acetylchlorine receptors on the diaphram of a bite victim, leading to the loss of function of the diaphragm muscle tissue and eventually death. In order to develop more potent antivenoms, scientists have studied what happens to toxin once it has bound the acetylchlorine receptors. They have found that the toxin is released from the receptor in a process that can be described by the rate law:

 

Rate= k [acetylchlorine receptor-toxin complex]

 

 

If the activation energy of this reaction at 37.0°C is 26.2 kJ/mol and A=0.850 s^-1, what is the rate of the reaction of you have a 0.200M solution of receptor-toxin complex at 37.0°C

Answer 1

First, you must find the value of k (the rate constant).  From the Arrhenius equation, you can do that:

ln k = ln A + Ea/RT 

A = 0.850 s^-1

Ea = 26.2 kJ/mole

R = 8.314 J/mole-K = 0.008314 kJ/mole-K

T = 37 + 273 = 310 K

Plug these values into the Arrhenius equation and solve for k.  Be sure to use the correct R value, i.e 8.314 J/Kmol if you use Ea in j/mole or 0.008314 kJ/Kmole if you use Ea in kJ.

 

Once you have k, use it in the rate equation:

rate = k[R-X] where [R-X] = receptor-toxin complex concentration = 0.200 M 

solve for rate

Be careful to keep the units proper.