The length of a rectangle is 5 ft longer than its width. If the perimeter of the rectangle is 42 ft, find its area

Question

The length of a rectangle is 5 ft longer than its width. If the perimeter of the rectangle is 42 ft, find its area 

Answer 1

L = w + 5

 

P = 2(L+w) = 42

L + w = 21

 

w+5 + w = 21

2w + 5 = 21

2w = 16

w = 8 ft

 

L = w+5 = 13 ft.

 

Rectangle is 13 ft by 8 ft

Area = 13(8) = 104 ft²

 

Check:  P = 2(L+w) = 2(13+8) = 2(21) = 42 ft