Arthur D. answered 02/10/18
Tutor
4.9
(274)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
n=7.765765765...
3 digits repeat
multiply both sides by 103 or 1000
1000n=7765.765765765...
subtract the first equation from the second equation
1000n=7765.765765765...
-
n= 7.765765765...
999n=7758 (the decimal parts are eliminated)
n=7758/999
now simplify by dividing both terms by 9
n=862/111
if the repetend has no lag, then put the repetend over 9, or 99, or 999, etc depending on how many digits repeat
7.765765765...=7 765/999=7758/999=862/111 (3 digits repeat thus the 999)

Bobosharif S.
02/10/18