A rectangle has a perimeter of 204. Its length is 6 feet longer than twice its width. Find the dimensions of this rectangle.

Question

,,,,,,,,,,,,,,,,,,,,,,,,,,,,l

Answer 1

The formula for perimeter is 2*l + 2*w

 

The question tells us that l = 2*w + 6

 

We can substitute "2*w + 6" for l in the perimeter equation.

 

204 = 2(2*w + 6) + 2*w

204 = 4*w + 12 + 2*w

204 = 6*w + 12

204 - 12 = 6*w

192 = 6*w

32 = w

 

Substitute this "w" into the length equation.

l = 2*w + 6

l = 2*32 + 6

l = 64 + 6

l = 70

 

The dimensions of the rectangle are 70ft by 32ft.