It's usually helpful to treat work rate problems in terms of work performed per unit time, not time required to complete the entire job.
Betty can paint a house in 14 hours, so she can paint 1/14 of a house in one hour.
Karen can paint a house in x hours, and the two women working together can paint the house in 2x/3 hours. So Karen can paint 1/x of a house in one hour and both can do the job in 3/2x hours.
Add the "work per hour" figures:
1/14 + 1/x = 3/2x
Common denominator is 14x.
x/14x + 14/14x = 21/14x
Disregard the denominators.
x + 14 = 21
x = 7
Now let's see if the answer makes sense.
We already knew Betty could paint a house in 14 hours, or 1/14 of a house in one hour.
We now know Karen can paint a house in 7 hours, or 1/7 of a house in one hour.
1/14 + 1/7 = 3/14. The two women can paint 3/14 of a house in an hour, or an entire house in 14/3 or 4 2/3 hours.
4 2/3 is 2/3 of 7.
Betty can paint a house in 14 hours, so she can paint 1/14 of a house in one hour.
Karen can paint a house in x hours, and the two women working together can paint the house in 2x/3 hours. So Karen can paint 1/x of a house in one hour and both can do the job in 3/2x hours.
Add the "work per hour" figures:
1/14 + 1/x = 3/2x
Common denominator is 14x.
x/14x + 14/14x = 21/14x
Disregard the denominators.
x + 14 = 21
x = 7
Now let's see if the answer makes sense.
We already knew Betty could paint a house in 14 hours, or 1/14 of a house in one hour.
We now know Karen can paint a house in 7 hours, or 1/7 of a house in one hour.
1/14 + 1/7 = 3/14. The two women can paint 3/14 of a house in an hour, or an entire house in 14/3 or 4 2/3 hours.
4 2/3 is 2/3 of 7.
Star M.
02/04/18