
TJ W. answered 02/05/18
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Let's define Helen's age as H, Ray's age as R, and Danny's age as D. Doing this allows us to set up a system of equations to solve this problem.
Since Helen is 1/2 of Ray's age, we can say that:
H=1/2*R We can multiply both sides of the equation to make it
1) R=2H
Doing the same for Ray, we can say:
R=4/7*D Multiplying both sides by 7 gives us
2) 7R=4D
We can't leave Danny out, either!
3) D=H+15
Since we have three equations and three unknowns, we can solve this system of equations. The easiest method, in this case, would be substitution.
We can start by substituting the R in equation 2 with equation 1. That gives us
7(2H)=4D
Dividing both sides by 2 gives us
4) 7H=2D
Plugging 3 into 4 gives us
7H=2(H+15).
Simplifying
7H=2H+30
5H=30
5) H=6:
So Helen is 6 years old. Since we know (from equation 1) that Ray is twice as old as Helen, we can plug 5 into 1 to get Ray's age:
R=2(6)
6) R=12
That gives us our answer. Ray is 12 years old.
Now, plugging 6 into 2 will give us Danny's age as 21, which also satisfies equation 3. Each person's age is as follows:
Danny = 21 years old
Helen = 6 years old
Ray = 12 years old