Shailendra P. answered • 01/30/18

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Physics and Mathematics Tutor (B. Tech. from I.I.T. India)

a. PV = n

_{1}kT_{1}= n_{2}kT_{2}where n_{1}and n_{2}are number of molecules of oxygen and hydrogen respectively._{} => n

_{1}/ n_{2}= T_{2}/ T_{1}= 200 / 400 = 1 / 2b. m

_{1}/ m_{2}= (n_{1}* 32)/ (n_{2}* 2) = 8, molecular weight of O_{2}= M_{1}= 32, molecular weight of H_{2}= M_{2}= 2c. KE

_{1}/ KE_{2}= T_{1 / }T_{2 }= 400 / 200 = 2d. V

_{1}/ V_{2}= √[(T_{1}M_{2}) / (T_{2}M_{1})] = √[(400 * 2) / (200 * 32)] = 1/(2√2)