what is the answer for this 36y4-25y2 ?

Question

algebra 1 & it's hard for me so I am seeking the answer. please help!

Answer 1

You need to factor this. First factor out a y².

Notice:

36y²=  (6y)²

25 = 5²

The factorization of a²-b² is always (a-b)(a+b). This is called the difference of two squares.

 

So by the difference of two squares the factorization is y²(6y-5)(6y+5).

If by chance this is 36y⁴-25y²=0, then we'd need to take it one step further. With our factorization we set y²=0 to get y=0,  6y-5 =0 gives y = 5/6, and 6y+5 =0 gives y = -5/6.

 

Hope this helps!

-Devin

Answer 2

this expression would be y² (36y²- 25) = y² (6y+5)(6y-5), now it s up to you, what you are going to do with that.