Gaby, there are two different ways to solve this system.
First, since y has a "value" in the 2nd equation, we can substitute it for y in the first equation.
2x + (x - 5) = 1
2x + x - 5 = 1
3x = 6
x = 2
Now, we substitute our value for x into either equation.
y = 2 - 5
y = -3
Another way to solve it is to solve the 1st equation for y.
y = -2x + 1
Now we have two "values" for y, so they equal each other.
-2x + 1 = x - 5
-3x = -6
x = 2
y = 2 - 5
y = -3
Either way, pur solution is (2,-3).
