Solve (8)^x - 4^3-x = 0

Question

Please show all steps. I do not have a proper calculator.

 

if the answer is not an integer, enter it as a decimal rounded to the nearest hundredth, if needed

Answer 1

8^x - 4^3-x = 0

 

8^x = 4^3-x               change everything to base 2 using 8 = 2³     and      4 = 2²

 

2^3x = 2^2(3-x)                when two exponents with the same base are equal, the powers must be equal

 

3x = 2(3-x)           now you can solve for x