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The standard forms of a logarithmic function are these, x = b^{y} which is written y = log_{b}(x). When the b (base) is 10 it's not indicated but implied instead. So we can't assume that x=10 here because it's not the base. The way to solve this is through log laws.

We must first separate the two types of logs we have, ones with the variable and the others with the constants. By doing this we get:

2log(x) = log(5)-log(4)

By log laws, log(x)-log(y)=log(x/y) thus we get log(5/4) on the right side.

Next we divide by 2 on each side to get:

log(x)=1/2log(5/4). Again, by log laws the 1/2 becomes the exponent to the 5/4 inside the log function:

log(x)=log((5/4)^{(1/2)}). From here we can remove the log on both sides because for both sides to equal each other, we just need x to equal (5/4)^{(1/2)}. And now the final steps are just to clean up the right side: