A line passes through point (-2, 5) and has a slope of 2/3 . Points A(x, 3) and B(-2, y) lie on the line. The value of x is , and the value of y is .

Question

 Really need help with this one question! Please try and help me out. Thank you.

Answer 1

First, find the equation of the line by using the Point-Slope Equation for a line.

y - y₁ = m(x - x₁)

y - 5 = (2/3)(x + 2)

y - 5 = (2/3)x + 4/3

y = (2/3)x +  19/3

 

If y = 3, 3 = (2/3)x + 19/3

9 = 2x + 19

-10 = 2x

-5 = x

 

If x = -2, y = (2/3)(-2) + 19/3

y = -4/3 + 19/3

y = 5

 

 

 

Answer 2

GIVEN: A line passes through point (-2, 5) and has a slope of 2/3.

From this, you can obtain the equation of the line (use Point Slope form).

 

Point A has y value 3 given; substitute that, and compute (obtain) what x must be.

 

Point B has x value -2 given; substitute that, and obtain what y must be.

 

This is doable in three straightforward steps, as indicated above.