Rotational period

Question

A star is rotating at 5.55x10^-5Πrad/s, its velocity decelerates at a constant rate of 0.5x10^-9 π rad/s².

What is the current rotational period of that star (in hours)?
 What is the formula you use to solve this formula

Answer 1

If you have an angular velocity ω, you can get the period T from 

 

ω = 2π/T ⇒

 

T = 2π/ω = 2π / (5.55 x 10^-5 π rad/s) ≅ 36036 s ≅ 10.01 h

 

However, the period is increasing as ω slows down.