Sumeet D.

asked • 12/30/17

Simultaneous Equations

Andrewe, Melinda, and Ben had $10, $12,$15 respectively. Andrew brought 8 apples and 5 oranges, Melinda bought 6 apples and 10 oranges and Ben bought 12 apples and 20 oranges. Let the cost of an apple be $x and $y respectively.

1) The amount of change Melinda received was $4 more than the amount of change Ben had received. Form an equation in x and y.

1 Expert Answer

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Andy C. answered • 12/30/17

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I have already solved this problem and the numbers have not changed.
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Sumeet D.

I just need help trying to make the equation for question 1) the amount of change Melinda received was $4 more than the amount of change Ben had received. Form an equation in x and y. Can you just do that for me please?
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12/30/17

Andrew M.

Andy did form your equations in x and y from the statement:
 
8x + 5y = 10               {equation 1}
6x + 10y + c+4 = 12   {equation 2}
12x + 20y + c = 15     {equation 3}
 
The 2nd and 3rd equations take into account the change that Ben received as c
and Melinda's change as c+4
 
Then he combined the two by subtracting equation 2 from equation 3 to create:
6x + 10y = 7
 
At that point there were 2 simultaneous equations in x and y:
 
8x + 5y = 10
6x + 10y = 7
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12/30/17

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