Ask a question

Can you help me with a math word problem?

The ratio of Jim's money to Peter's money was 4:7 at first.  After Jim spent 1/2 of his money and Peter spent $60, Peter had twice as much money as Jim.  How much money did Jim have at first?


1 Answer by Expert Tutors

Tutors, sign in to answer this question.
Roman C. | Masters of Education Graduate with Mathematics ExpertiseMasters of Education Graduate with Mathe...
4.9 4.9 (331 lesson ratings) (331)

Let peter have Jim have $4x. Then the given ratio means that Peter has $7x.

Since Jim spent half his money, he now has $2x dollars.

Peter spent $60 and thus now has $(7x-60).

The final ratio of Jim's money to Peter's money is therefore 2x : (7x-60). This is given as 1:2.

Now we just need to solve the proportion by cross-multiplying.

2x : (7x - 60) = 1 : 2

1*(7x - 60) = 2*2x

7x - 60 = 4x

3x = 60

x = 20. Therefore Jim originally had $4x = $80.