Write a equation.

Question

Write a equation for a circle that has a center at ( -6 , 5 ) and passes through the point ( -11 , 3 )

Answer 1

center at (-6,5) and goes through the point (-11,3)

(x-h)²+(y-k)²=r² where the center is (h,k) and r is the radius

first find the radius using the distance formula

√((-6-[-11])²+(5-3)²)

√(5²+2²)

√29=r, the radius

(x+6)²+(y-5)²=(√29)²

(x+6)²+(y-5)²=29