suppose cos theta = 5/9 and 3pi/2<theta<2pi

Question

 suppose cos theta = 5/9 and 3pi/2<theta<2pi. Sketch theta and theta/2 in standard position and label the intersection of these terminal sides with the unit circle.

Answer 1

The inverse cosine or arccos of 5/9 is 56.251 degrees

 

Since the domain is in the 4th quadrant, the angle is 360-56.251 = 303.749

 

or roughly 303 and 3/4 degrees